\left\{ \begin{array} { l } { 2 x + y = 5 } \\ { 3 y + 1 = 10 } \end{array} \right.
Solve for x, y
x=1
y=3
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3y=10-1
Consider the second equation. Subtract 1 from both sides.
3y=9
Subtract 1 from 10 to get 9.
y=\frac{9}{3}
Divide both sides by 3.
y=3
Divide 9 by 3 to get 3.
2x+3=5
Consider the first equation. Insert the known values of variables into the equation.
2x=5-3
Subtract 3 from both sides.
2x=2
Subtract 3 from 5 to get 2.
x=\frac{2}{2}
Divide both sides by 2.
x=1
Divide 2 by 2 to get 1.
x=1 y=3
The system is now solved.
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