\left\{ \begin{array} { l } { 2 x + 5 y = 3 } \\ { 3 x - 11 = 7 } \end{array} \right.
Solve for x, y
x=6
y = -\frac{9}{5} = -1\frac{4}{5} = -1.8
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3x=7+11
Consider the second equation. Add 11 to both sides.
3x=18
Add 7 and 11 to get 18.
x=\frac{18}{3}
Divide both sides by 3.
x=6
Divide 18 by 3 to get 6.
2\times 6+5y=3
Consider the first equation. Insert the known values of variables into the equation.
12+5y=3
Multiply 2 and 6 to get 12.
5y=3-12
Subtract 12 from both sides.
5y=-9
Subtract 12 from 3 to get -9.
y=-\frac{9}{5}
Divide both sides by 5.
x=6 y=-\frac{9}{5}
The system is now solved.
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