\left\{ \begin{array} { l } { 2 x + 3 y = 7 } \\ { 2 x + 2 y - 2 y = 1 } \end{array} \right.
Solve for x, y
x=\frac{1}{2}=0.5
y=2
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2x=1
Consider the second equation. Combine 2y and -2y to get 0.
x=\frac{1}{2}
Divide both sides by 2.
2\times \frac{1}{2}+3y=7
Consider the first equation. Insert the known values of variables into the equation.
1+3y=7
Multiply 2 and \frac{1}{2} to get 1.
3y=7-1
Subtract 1 from both sides.
3y=6
Subtract 1 from 7 to get 6.
y=\frac{6}{3}
Divide both sides by 3.
y=2
Divide 6 by 3 to get 2.
x=\frac{1}{2} y=2
The system is now solved.
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