Solve {l}{2x+3=5}{3y+x=20}

$$\left\{ \begin{array} { l } { 2 x + 3 = 5 } \\ { 3 y + x = 20 } \end{array} \right.$$

Solve for x, y

$$x=1$$

$$y = \frac{19}{3} = 6\frac{1}{3} \approx 6.333333333$$

Solution Steps

Consider the first equation. Subtract 3 from both sides.

$$2x=5-3$$

Subtract 3 from 5 to get 2.

$$2x=2$$

Divide both sides by 2.

$$x=\frac{2}{2}$$

Divide 2 by 2 to get 1.

$$x=1$$

Consider the second equation. Insert the known values of variables into the equation.

$$3y+1=20$$

Subtract 1 from both sides.

$$3y=20-1$$

Subtract 1 from 20 to get 19.

$$3y=19$$

Divide both sides by 3.

$$y=\frac{19}{3}$$

The system is now solved.

$$x=1 y=\frac{19}{3}$$