\left\{ \begin{array} { l } { 2 a - 2 = 1 } \\ { 8 + 1 = 2 b - 1 } \end{array} \right.
Solve for a, b
a = \frac{3}{2} = 1\frac{1}{2} = 1.5
b=5
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2a=1+2
Consider the first equation. Add 2 to both sides.
2a=3
Add 1 and 2 to get 3.
a=\frac{3}{2}
Divide both sides by 2.
9=2b-1
Consider the second equation. Add 8 and 1 to get 9.
2b-1=9
Swap sides so that all variable terms are on the left hand side.
2b=9+1
Add 1 to both sides.
2b=10
Add 9 and 1 to get 10.
b=\frac{10}{2}
Divide both sides by 2.
b=5
Divide 10 by 2 to get 5.
a=\frac{3}{2} b=5
The system is now solved.
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