\left\{ \begin{array} { l } { 16 + 4 b + c = 0 } \\ { c = 4 } \end{array} \right.
Solve for b, c
b=-5
c=4
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16+4b+4=0
Consider the first equation. Insert the known values of variables into the equation.
20+4b=0
Add 16 and 4 to get 20.
4b=-20
Subtract 20 from both sides. Anything subtracted from zero gives its negation.
b=\frac{-20}{4}
Divide both sides by 4.
b=-5
Divide -20 by 4 to get -5.
b=-5 c=4
The system is now solved.
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