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8y+8=y
Consider the first equation. Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 8y, the least common multiple of y,8.
8y+8-y=0
Subtract y from both sides.
7y+8=0
Combine 8y and -y to get 7y.
7y=-8
Subtract 8 from both sides. Anything subtracted from zero gives its negation.
y=-\frac{8}{7}
Divide both sides by 7.
\frac{1}{x}+\frac{4}{-\frac{8}{7}}=\frac{1}{4}
Consider the second equation. Insert the known values of variables into the equation.
4+4x\times \frac{4}{-\frac{8}{7}}=x
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 4x, the least common multiple of x,4.
4+4x\times 4\left(-\frac{7}{8}\right)=x
Divide 4 by -\frac{8}{7} by multiplying 4 by the reciprocal of -\frac{8}{7}.
4+4x\left(-\frac{7}{2}\right)=x
Multiply 4 and -\frac{7}{8} to get -\frac{7}{2}.
4-14x=x
Multiply 4 and -\frac{7}{2} to get -14.
4-14x-x=0
Subtract x from both sides.
4-15x=0
Combine -14x and -x to get -15x.
-15x=-4
Subtract 4 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-4}{-15}
Divide both sides by -15.
x=\frac{4}{15}
Fraction \frac{-4}{-15} can be simplified to \frac{4}{15} by removing the negative sign from both the numerator and the denominator.
y=-\frac{8}{7} x=\frac{4}{15}
The system is now solved.