\left\{ \begin{array} { l } { 0 = 3 k + b } \\ { - 2 = b } \end{array} \right.
Solve for k, b
k=\frac{2}{3}\approx 0.666666667
b=-2
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b=-2
Consider the second equation. Swap sides so that all variable terms are on the left hand side.
0=3k-2
Consider the first equation. Insert the known values of variables into the equation.
3k-2=0
Swap sides so that all variable terms are on the left hand side.
3k=2
Add 2 to both sides. Anything plus zero gives itself.
k=\frac{2}{3}
Divide both sides by 3.
k=\frac{2}{3} b=-2
The system is now solved.
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