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5x-8=-4
Consider the first equation. Multiply both sides of the equation by 40, the least common multiple of 8,5,10.
5x=-4+8
Add 8 to both sides.
5x=4
Add -4 and 8 to get 4.
x=\frac{4}{5}
Divide both sides by 5.
\frac{\frac{4}{5}}{5}-\frac{y}{4}=-\frac{69}{40}
Consider the second equation. Insert the known values of variables into the equation.
8\times \frac{4}{5}-10y=-69
Multiply both sides of the equation by 40, the least common multiple of 5,4,40.
\frac{32}{5}-10y=-69
Multiply 8 and \frac{4}{5} to get \frac{32}{5}.
-10y=-69-\frac{32}{5}
Subtract \frac{32}{5} from both sides.
-10y=-\frac{377}{5}
Subtract \frac{32}{5} from -69 to get -\frac{377}{5}.
y=\frac{-\frac{377}{5}}{-10}
Divide both sides by -10.
y=\frac{-377}{5\left(-10\right)}
Express \frac{-\frac{377}{5}}{-10} as a single fraction.
y=\frac{-377}{-50}
Multiply 5 and -10 to get -50.
y=\frac{377}{50}
Fraction \frac{-377}{-50} can be simplified to \frac{377}{50} by removing the negative sign from both the numerator and the denominator.
x=\frac{4}{5} y=\frac{377}{50}
The system is now solved.