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x+y+x-y=24
Consider the first equation. Multiply both sides of the equation by 6.
2x+y-y=24
Combine x and x to get 2x.
2x=24
Combine y and -y to get 0.
x=\frac{24}{2}
Divide both sides by 2.
x=12
Divide 24 by 2 to get 12.
\frac{2\times 12+y}{4}-\frac{2\times 12-5y}{3}=5
Consider the second equation. Insert the known values of variables into the equation.
3\left(2\times 12+y\right)-4\left(2\times 12-5y\right)=60
Multiply both sides of the equation by 12, the least common multiple of 4,3.
3\left(24+y\right)-4\left(2\times 12-5y\right)=60
Multiply 2 and 12 to get 24.
72+3y-4\left(2\times 12-5y\right)=60
Use the distributive property to multiply 3 by 24+y.
72+3y-4\left(24-5y\right)=60
Multiply 2 and 12 to get 24.
72+3y-96+20y=60
Use the distributive property to multiply -4 by 24-5y.
-24+3y+20y=60
Subtract 96 from 72 to get -24.
-24+23y=60
Combine 3y and 20y to get 23y.
23y=60+24
Add 24 to both sides.
23y=84
Add 60 and 24 to get 84.
y=\frac{84}{23}
Divide both sides by 23.
x=12 y=\frac{84}{23}
The system is now solved.