Solve {l}{-1+0/2=3+x/2}{0+y/2=-2+0/2}

$$\left\{ \begin{array} { l } { \frac { - 1 + 0 } { 2 } = \frac { 3 + x } { 2 } } \\ { \frac { 0 + y } { 2 } = \frac { - 2 + 0 } { 2 } } \end{array} \right.$$

Solve for x, y

$$x=-4$$

$$y=-2$$

Solution Steps

Consider the first equation. Multiply both sides of the equation by 2.

$$-1+0=3+x$$

Add -1 and 0 to get -1.

$$-1=3+x$$

Swap sides so that all variable terms are on the left hand side.

$$3+x=-1$$

Subtract 3 from both sides.

$$x=-1-3$$

Subtract 3 from -1 to get -4.

$$x=-4$$

Consider the second equation. Multiply both sides of the equation by 2.

$$0+y=-2+0$$

Anything plus zero gives itself.

$$y=-2+0$$

Add -2 and 0 to get -2.

$$y=-2$$

The system is now solved.

$$x=-4 y=-2$$