\left\{ \begin{array} { c } { x - y - 4 = 0 } \\ { x + 3 = 0 } \end{array} \right.
Solve for x, y
x=-3
y=-7
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x=-3
Consider the second equation. Subtract 3 from both sides. Anything subtracted from zero gives its negation.
-3-y-4=0
Consider the first equation. Insert the known values of variables into the equation.
-7-y=0
Subtract 4 from -3 to get -7.
-y=7
Add 7 to both sides. Anything plus zero gives itself.
y=-7
Divide both sides by -1.
x=-3 y=-7
The system is now solved.
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