\left\{ \begin{array} { c } { a - b + c = 0 } \\ { 9 a + 3 b + c = 0 } \\ { c = 9 } \end{array} \right.
Solve for a, b, c
a=-3
b=6
c=9
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c=9 9a+3b+c=0 a-b+c=0
Reorder the equations.
9a+3b+9=0 a-b+9=0
Substitute 9 for c in the second and third equation.
b=-3-3a a=b-9
Solve these equations for b and a respectively.
a=-3-3a-9
Substitute -3-3a for b in the equation a=b-9.
a=-3
Solve a=-3-3a-9 for a.
b=-3-3\left(-3\right)
Substitute -3 for a in the equation b=-3-3a.
b=6
Calculate b from b=-3-3\left(-3\right).
a=-3 b=6 c=9
The system is now solved.
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