\left\{ \begin{array} { c } { - x + \frac { 1 } { 3 } y = 0 } \\ { 4 x + 2 y + 3 z = 1 } \\ { \frac { 1 } { 4 } x + \frac { 1 } { 2 } z = 0 } \end{array} \right.
Solve for x, y, z
x=\frac{2}{17}\approx 0.117647059
y=\frac{6}{17}\approx 0.352941176
z=-\frac{1}{17}\approx -0.058823529
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x=\frac{1}{3}y
Solve -x+\frac{1}{3}y=0 for x.
4\times \frac{1}{3}y+2y+3z=1 \frac{1}{4}\times \frac{1}{3}y+\frac{1}{2}z=0
Substitute \frac{1}{3}y for x in the second and third equation.
y=-\frac{9}{10}z+\frac{3}{10} z=-\frac{1}{6}y
Solve these equations for y and z respectively.
z=-\frac{1}{6}\left(-\frac{9}{10}z+\frac{3}{10}\right)
Substitute -\frac{9}{10}z+\frac{3}{10} for y in the equation z=-\frac{1}{6}y.
z=-\frac{1}{17}
Solve z=-\frac{1}{6}\left(-\frac{9}{10}z+\frac{3}{10}\right) for z.
y=-\frac{9}{10}\left(-\frac{1}{17}\right)+\frac{3}{10}
Substitute -\frac{1}{17} for z in the equation y=-\frac{9}{10}z+\frac{3}{10}.
y=\frac{6}{17}
Calculate y from y=-\frac{9}{10}\left(-\frac{1}{17}\right)+\frac{3}{10}.
x=\frac{1}{3}\times \frac{6}{17}
Substitute \frac{6}{17} for y in the equation x=\frac{1}{3}y.
x=\frac{2}{17}
Calculate x from x=\frac{1}{3}\times \frac{6}{17}.
x=\frac{2}{17} y=\frac{6}{17} z=-\frac{1}{17}
The system is now solved.
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