Solve lambda^2-5x+6=0

$$\lambda ^ { 2 } - 5 x + 6 = 0$$

Solve for x

$$x=\frac{\lambda ^{2}+6}{5}$$

Steps for Solving Linear Equation

Subtract \lambda ^{2} from both sides. Anything subtracted from zero gives its negation.

$$-5x+6=-\lambda ^{2}$$

Subtract 6 from both sides.

$$-5x=-\lambda ^{2}-6$$

Divide both sides by -5.

$$\frac{-5x}{-5}=\frac{-\lambda ^{2}-6}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$x=\frac{-\lambda ^{2}-6}{-5}$$

Divide -\lambda ^{2}-6 by -5.

$$x=\frac{\lambda ^{2}+6}{5}$$

Solve for λ (complex solution)

$$\lambda =-\sqrt{5x-6}$$

$$\lambda =\sqrt{5x-6}$$

Solve for λ

$$\lambda =\sqrt{5x-6}$$

$$\lambda =-\sqrt{5x-6}\text{, }x\geq \frac{6}{5}$$