Solve ∫ (from 1 to 5) of 2x-1 wrt x

$$\int_{ 1 }^{ 5 } 2x-1 d x$$

Evaluate

$$20$$

Solution Steps

Evaluate the indefinite integral first.

$$\int 2x-1\mathrm{d}x$$

Integrate the sum term by term.

$$\int 2x\mathrm{d}x+\int -1\mathrm{d}x$$

Factor out the constant in each of the terms.

$$2\int x\mathrm{d}x+\int -1\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply 2 times \frac{x^{2}}{2}.

$$x^{2}+\int -1\mathrm{d}x$$

Find the integral of -1 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$x^{2}-x$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$5^{2}-5-\left(1^{2}-1\right)$$

Simplify.

$$20$$