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\int 100+50x^{2}\mathrm{d}x
Evaluate the indefinite integral first.
\int 100\mathrm{d}x+\int 50x^{2}\mathrm{d}x
Integrate the sum term by term.
\int 100\mathrm{d}x+50\int x^{2}\mathrm{d}x
Factor out the constant in each of the terms.
100x+50\int x^{2}\mathrm{d}x
Find the integral of 100 using the table of common integrals rule \int a\mathrm{d}x=ax.
100x+\frac{50x^{3}}{3}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Multiply 50 times \frac{x^{3}}{3}.
100\times 4+\frac{50}{3}\times 4^{3}-\left(100\times 0+\frac{50}{3}\times 0^{3}\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{4400}{3}
Simplify.