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\int -x+5\mathrm{d}x
Evaluate the indefinite integral first.
\int -x\mathrm{d}x+\int 5\mathrm{d}x
Integrate the sum term by term.
-\int x\mathrm{d}x+\int 5\mathrm{d}x
Factor out the constant in each of the terms.
-\frac{x^{2}}{2}+\int 5\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply -1 times \frac{x^{2}}{2}.
-\frac{x^{2}}{2}+5x
Find the integral of 5 using the table of common integrals rule \int a\mathrm{d}x=ax.
-\frac{4^{2}}{2}+5\times 4-\left(-\frac{\left(-1\right)^{2}}{2}+5\left(-1\right)\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{35}{2}
Simplify.