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\int \sin(x)-\cos(x)\mathrm{d}x
Evaluate the indefinite integral first.
\int \sin(x)\mathrm{d}x+\int -\cos(x)\mathrm{d}x
Integrate the sum term by term.
\int \sin(x)\mathrm{d}x-\int \cos(x)\mathrm{d}x
Factor out the constant in each of the terms.
-\cos(x)-\int \cos(x)\mathrm{d}x
Use \int \sin(x)\mathrm{d}x=-\cos(x) from the table of common integrals to obtain the result.
-\cos(x)-\sin(x)
Use \int \cos(x)\mathrm{d}x=\sin(x) from the table of common integrals to obtain the result.
-\cos(\pi )-\sin(\pi )-\left(-\cos(\frac{1}{4}\pi )-\sin(\frac{1}{4}\pi )\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
1+\sqrt{2}
Simplify.