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Differentiate w.r.t. x
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\int y^{2}\mathrm{d}y
Evaluate the indefinite integral first.
\frac{y^{3}}{3}
Since \int y^{k}\mathrm{d}y=\frac{y^{k+1}}{k+1} for k\neq -1, replace \int y^{2}\mathrm{d}y with \frac{y^{3}}{3}.
\frac{1}{3}\left(x^{2}\right)^{3}-\frac{x^{3}}{3}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{-x^{3}+x^{6}}{3}
Simplify.