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\int _{3}^{50}x^{2}+8x\mathrm{d}x
Use the distributive property to multiply x by x+8.
\int x^{2}+8x\mathrm{d}x
Evaluate the indefinite integral first.
\int x^{2}\mathrm{d}x+\int 8x\mathrm{d}x
Integrate the sum term by term.
\int x^{2}\mathrm{d}x+8\int x\mathrm{d}x
Factor out the constant in each of the terms.
\frac{x^{3}}{3}+8\int x\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}.
\frac{x^{3}}{3}+4x^{2}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply 8 times \frac{x^{2}}{2}.
\frac{50^{3}}{3}+4\times 50^{2}-\left(\frac{3^{3}}{3}+4\times 3^{2}\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{154865}{3}
Simplify.