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\int 3x^{2}-x^{5}\mathrm{d}x
Evaluate the indefinite integral first.
\int 3x^{2}\mathrm{d}x+\int -x^{5}\mathrm{d}x
Integrate the sum term by term.
3\int x^{2}\mathrm{d}x-\int x^{5}\mathrm{d}x
Factor out the constant in each of the terms.
x^{3}-\int x^{5}\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}. Multiply 3 times \frac{x^{3}}{3}.
x^{3}-\frac{x^{6}}{6}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{5}\mathrm{d}x with \frac{x^{6}}{6}. Multiply -1 times \frac{x^{6}}{6}.
5^{3}-\frac{5^{6}}{6}-\left(3^{3}-\frac{3^{6}}{6}\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
-\frac{7154}{3}
Simplify.