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\int _{1}^{27}2\pi x^{4}\times 27\mathrm{d}x
To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.
\int _{1}^{27}54\pi x^{4}\mathrm{d}x
Multiply 2 and 27 to get 54.
\int 54\pi x^{4}\mathrm{d}x
Evaluate the indefinite integral first.
54\pi \int x^{4}\mathrm{d}x
Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.
54\pi \times \frac{x^{5}}{5}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{4}\mathrm{d}x with \frac{x^{5}}{5}.
\frac{54\pi x^{5}}{5}
Simplify.
\frac{54}{5}\pi \times 27^{5}-\frac{54}{5}\pi \times 1^{5}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{774840924\pi }{5}
Simplify.