Evaluate
\frac{31}{5}=6.2
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\int a^{4}\mathrm{d}a
Evaluate the indefinite integral first.
\frac{a^{5}}{5}
Since \int a^{k}\mathrm{d}a=\frac{a^{k+1}}{k+1} for k\neq -1, replace \int a^{4}\mathrm{d}a with \frac{a^{5}}{5}.
\frac{2^{5}}{5}-\frac{1^{5}}{5}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{31}{5}
Simplify.
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