Evaluate
16n+8
Differentiate w.r.t. n
16
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\int 1+2n\mathrm{d}x
Evaluate the indefinite integral first.
\left(1+2n\right)x
Find the integral of 1+2n using the table of common integrals rule \int a\mathrm{d}x=ax.
\left(1+2n\right)\times 8-\left(1+2n\right)\times 0
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
8+16n
Simplify.
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