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\int x^{2}+2x+4\mathrm{d}x
Evaluate the indefinite integral first.
\int x^{2}\mathrm{d}x+\int 2x\mathrm{d}x+\int 4\mathrm{d}x
Integrate the sum term by term.
\int x^{2}\mathrm{d}x+2\int x\mathrm{d}x+\int 4\mathrm{d}x
Factor out the constant in each of the terms.
\frac{x^{3}}{3}+2\int x\mathrm{d}x+\int 4\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}.
\frac{x^{3}}{3}+x^{2}+\int 4\mathrm{d}x
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply 2 times \frac{x^{2}}{2}.
\frac{x^{3}}{3}+x^{2}+4x
Find the integral of 4 using the table of common integrals rule \int a\mathrm{d}x=ax.
\frac{3^{3}}{3}+3^{2}+4\times 3-\left(\frac{0^{3}}{3}+0^{2}+4\times 0\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
30
Simplify.