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\int 80y^{2}\mathrm{d}y
Evaluate the indefinite integral first.
80\int y^{2}\mathrm{d}y
Factor out the constant using \int af\left(y\right)\mathrm{d}y=a\int f\left(y\right)\mathrm{d}y.
\frac{80y^{3}}{3}
Since \int y^{k}\mathrm{d}y=\frac{y^{k+1}}{k+1} for k\neq -1, replace \int y^{2}\mathrm{d}y with \frac{y^{3}}{3}.
\frac{80}{3}\times 20^{3}-\frac{80}{3}\times 0^{3}
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{640000}{3}
Simplify.