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\int 1.2-x\mathrm{d}x
Evaluate the indefinite integral first.
\int 1.2\mathrm{d}x+\int -x\mathrm{d}x
Integrate the sum term by term.
\int 1.2\mathrm{d}x-\int x\mathrm{d}x
Factor out the constant in each of the terms.
\frac{6x}{5}-\int x\mathrm{d}x
Find the integral of 1.2 using the table of common integrals rule \int a\mathrm{d}x=ax.
\frac{6x}{5}-\frac{x^{2}}{2}
Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. Multiply -1 times \frac{x^{2}}{2}.
1.2\times \frac{1}{10}\left(6-11^{\frac{1}{2}}\right)-\frac{1}{2}\times \left(\frac{1}{10}\left(6-11^{\frac{1}{2}}\right)\right)^{2}-\left(1.2\times \frac{1}{5}-\frac{\left(\frac{1}{5}\right)^{2}}{2}\right)
The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.
\frac{53}{200}-\frac{3\sqrt{11}}{50}
Simplify.