Solve ∫ 3(x-10)=2y-10

$$\int 3 ( x - 10 ) = 2 y - 10$$

Solve for y

$$y=\frac{3x^{2}}{4}+\frac{С}{2}-15x$$

Steps for Solving Linear Equation

Use the distributive property to multiply 3 by x-10.

$$\int 3x-30\mathrm{d}x=2y-10$$

Swap sides so that all variable terms are on the left hand side.

$$2y-10=\int 3x-30\mathrm{d}x$$

Add 10 to both sides.

$$2y=\int 3x-30\mathrm{d}x+10$$

The equation is in standard form.

$$2y=\frac{3x^{2}}{2}-30x+С$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{\frac{3x^{2}}{2}-30x+С}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{\frac{3x^{2}}{2}-30x+С}{2}$$

Divide \frac{3x^{2}}{2}-30x+С by 2.

$$y=\frac{3x^{2}}{4}+\frac{С}{2}-15x$$