Evaluate
2\sqrt{3}x+С
Differentiate w.r.t. x
2 \sqrt{3} = 3.464101615
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\sqrt{2+3+7}x
Find the integral of \sqrt{2+3+7} using the table of common integrals rule \int a\mathrm{d}x=ax.
2\sqrt{3}x
Simplify.
2\sqrt{3}x+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.
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