Solve ∫ x/2sqrt{x wrt x

$$\int \frac { x } { 2 \sqrt { x } } d x$$

Evaluate

$$\frac{x^{\frac{3}{2}}}{3}+С$$

Solution Steps

Factor the expressions that are not already factored in \frac{x}{2\sqrt{x}}.

$$\int \frac{x}{2\sqrt{x}}\mathrm{d}x$$

Cancel out \sqrt{x} in both numerator and denominator.

$$\int \frac{\sqrt{x}}{2}\mathrm{d}x$$

Factor out the constant using \int af\left(x\right)\mathrm{d}x=a\int f\left(x\right)\mathrm{d}x.

$$\frac{\int \sqrt{x}\mathrm{d}x}{2}$$

Rewrite \sqrt{x} as x^{\frac{1}{2}}. Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{\frac{1}{2}}\mathrm{d}x with \frac{x^{\frac{3}{2}}}{\frac{3}{2}}. Simplify.

$$\frac{x^{\frac{3}{2}}}{3}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{x^{\frac{3}{2}}}{3}+С$$

Differentiate w.r.t. x

$$\frac{\sqrt{x}}{2}$$