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Evaluate
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Differentiate w.r.t. x
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\int \frac{1}{64+9}\mathrm{d}x
Calculate 8 to the power of 2 and get 64.
\int \frac{1}{73}\mathrm{d}x
Add 64 and 9 to get 73.
\frac{x}{73}
Find the integral of \frac{1}{73} using the table of common integrals rule \int a\mathrm{d}x=ax.
\frac{x}{73}+С
If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.