Solve y-3/3-3=3(x+1)

$$\frac{ y-3 }{ 3 } -3=3(x+1)$$

Solve for x

$$x=\frac{y-21}{9}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$y-3-9=9\left(x+1\right)$$

Subtract 9 from -3 to get -12.

$$y-12=9\left(x+1\right)$$

Use the distributive property to multiply 9 by x+1.

$$y-12=9x+9$$

Swap sides so that all variable terms are on the left hand side.

$$9x+9=y-12$$

Subtract 9 from both sides.

$$9x=y-12-9$$

Subtract 9 from -12 to get -21.

$$9x=y-21$$

Divide both sides by 9.

$$\frac{9x}{9}=\frac{y-21}{9}$$

Dividing by 9 undoes the multiplication by 9.

$$x=\frac{y-21}{9}$$

Divide y-21 by 9.

$$x=\frac{y}{9}-\frac{7}{3}$$

Solve for y

$$y=9x+21$$

Solution Steps

Multiply both sides of the equation by 3.

$$y-3-9=9\left(x+1\right)$$

Subtract 9 from -3 to get -12.

$$y-12=9\left(x+1\right)$$

Use the distributive property to multiply 9 by x+1.

$$y-12=9x+9$$

Add 12 to both sides.

$$y=9x+9+12$$

Add 9 and 12 to get 21.

$$y=9x+21$$