Solve x-4/3-1=8/-8+6

$$\frac{ x-4 }{ 3-1 } = \frac{ 8 }{ -8+6 }$$

Solve for x

$$x=-4$$

Steps for Solving Linear Equation

Subtract 1 from 3 to get 2.

$$\frac{x-4}{2}=\frac{8}{-8+6}$$

Add -8 and 6 to get -2.

$$\frac{x-4}{2}=\frac{8}{-2}$$

Divide 8 by -2 to get -4.

$$\frac{x-4}{2}=-4$$

Divide each term of x-4 by 2 to get \frac{1}{2}x-2.

$$\frac{1}{2}x-2=-4$$

Add 2 to both sides.

$$\frac{1}{2}x=-4+2$$

Add -4 and 2 to get -2.

$$\frac{1}{2}x=-2$$

Multiply both sides by 2, the reciprocal of \frac{1}{2}.

$$x=-2\times 2$$

Multiply -2 and 2 to get -4.

$$x=-4$$