Solve for x
x=3
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2\left(x-3\right)-2\left(1-x\right)=x+1
Multiply both sides of the equation by 8, the least common multiple of 4,8.
2x-6-2\left(1-x\right)=x+1
Use the distributive property to multiply 2 by x-3.
2x-6-2+2x=x+1
Use the distributive property to multiply -2 by 1-x.
2x-8+2x=x+1
Subtract 2 from -6 to get -8.
4x-8=x+1
Combine 2x and 2x to get 4x.
4x-8-x=1
Subtract x from both sides.
3x-8=1
Combine 4x and -x to get 3x.
3x=1+8
Add 8 to both sides.
3x=9
Add 1 and 8 to get 9.
x=\frac{9}{3}
Divide both sides by 3.
x=3
Divide 9 by 3 to get 3.
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y = 3x + 4
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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