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Evaluate (complex solution)
true
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Solve for x
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1>0
Divide x by x to get 1.
\text{true}
Compare 1 and 0.
x<0 x<0
For the quotient to be positive, x and x have to be both negative or both positive. Consider the case when x and x are both negative.
x<0
The solution satisfying both inequalities is x<0.
x>0 x>0
Consider the case when x and x are both positive.
x>0
The solution satisfying both inequalities is x>0.
x\neq 0
The final solution is the union of the obtained solutions.