Solve for x
x\leq -\frac{20}{3}
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3x-4x\geq 5\left(x+8\right)
Multiply both sides of the equation by 15, the least common multiple of 5,15,3. Since 15 is positive, the inequality direction remains the same.
-x\geq 5\left(x+8\right)
Combine 3x and -4x to get -x.
-x\geq 5x+40
Use the distributive property to multiply 5 by x+8.
-x-5x\geq 40
Subtract 5x from both sides.
-6x\geq 40
Combine -x and -5x to get -6x.
x\leq \frac{40}{-6}
Divide both sides by -6. Since -6 is negative, the inequality direction is changed.
x\leq -\frac{20}{3}
Reduce the fraction \frac{40}{-6} to lowest terms by extracting and canceling out 2.
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