Solve v-u/a=z

$$\frac{ v-u }{ a } = z$$

Solve for a

$$\left\{\begin{matrix}a=\frac{v-u}{z}\text{, }&v\neq u\text{ and }z\neq 0\\a\neq 0\text{, }&z=0\text{ and }v=u\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable a cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by a.

$$v-u=za$$

Swap sides so that all variable terms are on the left hand side.

$$za=v-u$$

Divide both sides by z.

$$\frac{za}{z}=\frac{v-u}{z}$$

Dividing by z undoes the multiplication by z.

$$a=\frac{v-u}{z}$$

Variable a cannot be equal to 0.

$$a=\frac{v-u}{z}\text{, }a\neq 0$$

Solve for u

$$u=v-az$$

$$a\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by a.

$$v-u=za$$

Subtract v from both sides.

$$-u=za-v$$

The equation is in standard form.

$$-u=az-v$$

Divide both sides by -1.

$$\frac{-u}{-1}=\frac{az-v}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$u=\frac{az-v}{-1}$$

Divide za-v by -1.

$$u=v-az$$