Solve 9-7x/20=3-5x/11

$$\frac{ 9-7x }{ 20 } = \frac{ 3-5x }{ 11 }$$

Solve for x

$$x = -\frac{39}{23} = -1\frac{16}{23} \approx -1.695652174$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 220, the least common multiple of 20,11.

$$11\left(9-7x\right)=20\left(3-5x\right)$$

Use the distributive property to multiply 11 by 9-7x.

$$99-77x=20\left(3-5x\right)$$

Use the distributive property to multiply 20 by 3-5x.

$$99-77x=60-100x$$

Add 100x to both sides.

$$99-77x+100x=60$$

Combine -77x and 100x to get 23x.

$$99+23x=60$$

Subtract 99 from both sides.

$$23x=60-99$$

Subtract 99 from 60 to get -39.

$$23x=-39$$

Divide both sides by 23.

$$x=\frac{-39}{23}$$

Fraction \frac{-39}{23} can be rewritten as -\frac{39}{23} by extracting the negative sign.

$$x=-\frac{39}{23}$$