Solve 9/4+7/3+3/2=

$$\frac{ 9 }{ 4 } + \frac{ 7 }{ 3 } + \frac{ 3 }{ 2 } =$$

Evaluate

$$\frac{73}{12}\approx 6.083333333$$

Solution Steps

Least common multiple of 4 and 3 is 12. Convert \frac{9}{4} and \frac{7}{3} to fractions with denominator 12.

$$\frac{27}{12}+\frac{28}{12}+\frac{3}{2}$$

Since \frac{27}{12} and \frac{28}{12} have the same denominator, add them by adding their numerators.

$$\frac{27+28}{12}+\frac{3}{2}$$

Add 27 and 28 to get 55.

$$\frac{55}{12}+\frac{3}{2}$$

Least common multiple of 12 and 2 is 12. Convert \frac{55}{12} and \frac{3}{2} to fractions with denominator 12.

$$\frac{55}{12}+\frac{18}{12}$$

Since \frac{55}{12} and \frac{18}{12} have the same denominator, add them by adding their numerators.

$$\frac{55+18}{12}$$

Add 55 and 18 to get 73.

$$\frac{73}{12}$$

Factor

$$\frac{73}{2 ^ {2} \cdot 3} = 6\frac{1}{12} = 6.083333333333333$$