Solve 80-80/80-61=frac{100-{t}_{0}}{{t}_{0}-83}

$$\frac{ 80-80 }{ 80-61 } = \frac{ 100- { t }_{ 0 } }{ { t }_{ 0 } -83 }$$

Solve for t_0

$$t_{0}=100$$

Steps for Solving Linear Equation

Variable t_{0} cannot be equal to 83 since division by zero is not defined. Multiply both sides of the equation by t_{0}-83.

$$\left(\frac{1}{19}t_{0}-\frac{83}{19}\right)\left(80-80\right)=100-t_{0}$$

Subtract 80 from 80 to get 0.

$$\left(\frac{1}{19}t_{0}-\frac{83}{19}\right)\times 0=100-t_{0}$$

Anything times zero gives zero.

$$0=100-t_{0}$$

Swap sides so that all variable terms are on the left hand side.

$$100-t_{0}=0$$

Subtract 100 from both sides. Anything subtracted from zero gives its negation.

$$-t_{0}=-100$$

Multiply both sides by -1.

$$t_{0}=100$$