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\frac{\left(8-z\right)\left(z+8\right)}{\left(8+z\right)\left(z-8\right)}
Multiply \frac{8-z}{8+z} times \frac{z+8}{z-8} by multiplying numerator times numerator and denominator times denominator.
\frac{-\left(z-8\right)\left(z+8\right)}{\left(z-8\right)\left(z+8\right)}
Extract the negative sign in 8-z.
-1
Cancel out \left(z-8\right)\left(z+8\right) in both numerator and denominator.