Solve 8+5x/7+3x-4/8=x+1

$$\frac{ 8+5x }{ 7 } + \frac{ 3x-4 }{ 8 } =x+1$$

Solve for x

$$x=4$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 56, the least common multiple of 7,8.

$$8\left(8+5x\right)+7\left(3x-4\right)=56x+56$$

Use the distributive property to multiply 8 by 8+5x.

$$64+40x+7\left(3x-4\right)=56x+56$$

Use the distributive property to multiply 7 by 3x-4.

$$64+40x+21x-28=56x+56$$

Combine 40x and 21x to get 61x.

$$64+61x-28=56x+56$$

Subtract 28 from 64 to get 36.

$$36+61x=56x+56$$

Subtract 56x from both sides.

$$36+61x-56x=56$$

Combine 61x and -56x to get 5x.

$$36+5x=56$$

Subtract 36 from both sides.

$$5x=56-36$$

Subtract 36 from 56 to get 20.

$$5x=20$$

Divide both sides by 5.

$$x=\frac{20}{5}$$

Divide 20 by 5 to get 4.

$$x=4$$