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\frac{7\left(2-\sqrt{13}\right)}{\left(2+\sqrt{13}\right)\left(2-\sqrt{13}\right)}
Rationalize the denominator of \frac{7}{2+\sqrt{13}} by multiplying numerator and denominator by 2-\sqrt{13}.
\frac{7\left(2-\sqrt{13}\right)}{2^{2}-\left(\sqrt{13}\right)^{2}}
Consider \left(2+\sqrt{13}\right)\left(2-\sqrt{13}\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{7\left(2-\sqrt{13}\right)}{4-13}
Square 2. Square \sqrt{13}.
\frac{7\left(2-\sqrt{13}\right)}{-9}
Subtract 13 from 4 to get -9.
\frac{14-7\sqrt{13}}{-9}
Use the distributive property to multiply 7 by 2-\sqrt{13}.