Solve 6.02*10^23*3.9*10^25/235*10^-3

$$\frac{ 6.02 \times { 10 }^{ 23 } \times 3.9 \times { 10 }^{ 25 } }{ 235 \times { 10 }^{ -3 } }$$

Evaluate

$$\frac{4695600000000000000000000000000000000000000000000000}{47}\approx 9.990638298 \cdot 10^{49}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 23 and 25 to get 48.

$$\frac{6.02\times 10^{48}\times 3.9}{235\times 10^{-3}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{3.9\times 6.02\times 10^{51}}{235}$$

Multiply 3.9 and 6.02 to get 23.478.

$$\frac{23.478\times 10^{51}}{235}$$

Calculate 10 to the power of 51 and get 1000000000000000000000000000000000000000000000000000.

$$\frac{23.478\times 1000000000000000000000000000000000000000000000000000}{235}$$

Multiply 23.478 and 1000000000000000000000000000000000000000000000000000 to get 23478000000000000000000000000000000000000000000000000.

$$\frac{23478000000000000000000000000000000000000000000000000}{235}$$

Reduce the fraction \frac{23478000000000000000000000000000000000000000000000000}{235} to lowest terms by extracting and canceling out 5.

$$\frac{4695600000000000000000000000000000000000000000000000}{47}$$

Factor

$$\frac{3 \cdot 7 \cdot 13 \cdot 43 \cdot 2 ^ {49} \cdot 5 ^ {47}}{47} = 9.990638297872342 \times 10^{49}\frac{15}{47} = 9.990638297872342 \times 10^{49}$$