Solve 6/7x+32/7=-6

$$\frac{ 6 }{ 7 } x+ \frac{ 32 }{ 7 } =-6$$

Solve for x

$$x = -\frac{37}{3} = -12\frac{1}{3} \approx -12.333333333$$

Steps for Solving Linear Equation

Subtract \frac{32}{7} from both sides.

$$\frac{6}{7}x=-6-\frac{32}{7}$$

Convert -6 to fraction -\frac{42}{7}.

$$\frac{6}{7}x=-\frac{42}{7}-\frac{32}{7}$$

Since -\frac{42}{7} and \frac{32}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6}{7}x=\frac{-42-32}{7}$$

Subtract 32 from -42 to get -74.

$$\frac{6}{7}x=-\frac{74}{7}$$

Multiply both sides by \frac{7}{6}, the reciprocal of \frac{6}{7}.

$$x=-\frac{74}{7}\times \frac{7}{6}$$

Multiply -\frac{74}{7} times \frac{7}{6} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-74\times 7}{7\times 6}$$

Cancel out 7 in both numerator and denominator.

$$x=\frac{-74}{6}$$

Reduce the fraction \frac{-74}{6} to lowest terms by extracting and canceling out 2.

$$x=-\frac{37}{3}$$