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\frac{6}{5}x+\frac{1}{9}-\frac{2}{3}x=\frac{7}{3}
Subtract \frac{2}{3}x from both sides.
\frac{8}{15}x+\frac{1}{9}=\frac{7}{3}
Combine \frac{6}{5}x and -\frac{2}{3}x to get \frac{8}{15}x.
\frac{8}{15}x=\frac{7}{3}-\frac{1}{9}
Subtract \frac{1}{9} from both sides.
\frac{8}{15}x=\frac{21}{9}-\frac{1}{9}
Least common multiple of 3 and 9 is 9. Convert \frac{7}{3} and \frac{1}{9} to fractions with denominator 9.
\frac{8}{15}x=\frac{21-1}{9}
Since \frac{21}{9} and \frac{1}{9} have the same denominator, subtract them by subtracting their numerators.
\frac{8}{15}x=\frac{20}{9}
Subtract 1 from 21 to get 20.
x=\frac{20}{9}\times \frac{15}{8}
Multiply both sides by \frac{15}{8}, the reciprocal of \frac{8}{15}.
x=\frac{20\times 15}{9\times 8}
Multiply \frac{20}{9} times \frac{15}{8} by multiplying numerator times numerator and denominator times denominator.
x=\frac{300}{72}
Do the multiplications in the fraction \frac{20\times 15}{9\times 8}.
x=\frac{25}{6}
Reduce the fraction \frac{300}{72} to lowest terms by extracting and canceling out 12.