Solve 6/36+20/24+8/16-24/8

$$\frac{ 6 }{ 36 } + \frac{ 20 }{ 24 } + \frac{ 8 }{ 16 } - \frac{ 24 }{ 8 }$$

Evaluate

$$-\frac{3}{2}=-1.5$$

Solution Steps

Reduce the fraction \frac{6}{36} to lowest terms by extracting and canceling out 6.

$$\frac{1}{6}+\frac{20}{24}+\frac{8}{16}-\frac{24}{8}$$

Reduce the fraction \frac{20}{24} to lowest terms by extracting and canceling out 4.

$$\frac{1}{6}+\frac{5}{6}+\frac{8}{16}-\frac{24}{8}$$

Since \frac{1}{6} and \frac{5}{6} have the same denominator, add them by adding their numerators.

$$\frac{1+5}{6}+\frac{8}{16}-\frac{24}{8}$$

Add 1 and 5 to get 6.

$$\frac{6}{6}+\frac{8}{16}-\frac{24}{8}$$

Divide 6 by 6 to get 1.

$$1+\frac{8}{16}-\frac{24}{8}$$

Reduce the fraction \frac{8}{16} to lowest terms by extracting and canceling out 8.

$$1+\frac{1}{2}-\frac{24}{8}$$

Convert 1 to fraction \frac{2}{2}.

$$\frac{2}{2}+\frac{1}{2}-\frac{24}{8}$$

Since \frac{2}{2} and \frac{1}{2} have the same denominator, add them by adding their numerators.

$$\frac{2+1}{2}-\frac{24}{8}$$

Add 2 and 1 to get 3.

$$\frac{3}{2}-\frac{24}{8}$$

Divide 24 by 8 to get 3.

$$\frac{3}{2}-3$$

Convert 3 to fraction \frac{6}{2}.

$$\frac{3}{2}-\frac{6}{2}$$

Since \frac{3}{2} and \frac{6}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-6}{2}$$

Subtract 6 from 3 to get -3.

$$-\frac{3}{2}$$

Factor

$$-\frac{3}{2} = -1\frac{1}{2} = -1.5$$