Solve 5/6+11/7

$$\frac{ 5 }{ 6 } + 1 \frac { 1 } { 7 }$$

Evaluate

$$\frac{83}{42}\approx 1.976190476$$

Solution Steps

Multiply 1 and 7 to get 7.

$$\frac{5}{6}+\frac{7+1}{7}$$

Add 7 and 1 to get 8.

$$\frac{5}{6}+\frac{8}{7}$$

Least common multiple of 6 and 7 is 42. Convert \frac{5}{6} and \frac{8}{7} to fractions with denominator 42.

$$\frac{35}{42}+\frac{48}{42}$$

Since \frac{35}{42} and \frac{48}{42} have the same denominator, add them by adding their numerators.

$$\frac{35+48}{42}$$

Add 35 and 48 to get 83.

$$\frac{83}{42}$$

Factor

$$\frac{83}{2 \cdot 3 \cdot 7} = 1\frac{41}{42} = 1.9761904761904763$$