Solve 5/2y+2x=8

$$\frac{ 5 }{ 2 } y+2x=8$$

Solve for x

$$x=-\frac{5y}{4}+4$$

Steps for Solving Linear Equation

Subtract \frac{5}{2}y from both sides.

$$2x=8-\frac{5}{2}y$$

The equation is in standard form.

$$2x=-\frac{5y}{2}+8$$

Divide both sides by 2.

$$\frac{2x}{2}=\frac{-\frac{5y}{2}+8}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x=\frac{-\frac{5y}{2}+8}{2}$$

Divide 8-\frac{5y}{2} by 2.

$$x=-\frac{5y}{4}+4$$

Solve for y

$$y=\frac{16-4x}{5}$$

Steps for Solving Linear Equation

Subtract 2x from both sides.

$$\frac{5}{2}y=8-2x$$

Divide both sides of the equation by \frac{5}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{5}{2}y}{\frac{5}{2}}=\frac{8-2x}{\frac{5}{2}}$$

Dividing by \frac{5}{2} undoes the multiplication by \frac{5}{2}.

$$y=\frac{8-2x}{\frac{5}{2}}$$

Divide 8-2x by \frac{5}{2} by multiplying 8-2x by the reciprocal of \frac{5}{2}.

$$y=\frac{16-4x}{5}$$